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Quiz 2025 SAP C_HAMOD_2404: Professional Test SAP Certified Associate - Data Engineer - SAP HANA Tutorials

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SAP Certified Associate - Data Engineer - SAP HANA Sample Questions (Q68-Q73):

NEW QUESTION # 68
You combine two customer master data tables with a union node in a calculation view. Both master data tables include the same customer name. How do you ensure that each customer name appears only once in the results?

A. In the union node, map both source customer name columns to one target column.
B. Add an intersect node above the union node.
C. Define a restricted column in a union node.
D. Include an aggregation node above the union node.

Answer: D

Explanation:
To ensure that each customer name appears only once in the results when combining two tables using a union node, anaggregation nodeshould be added above the union node. The aggregation node consolidates duplicate entries by grouping the data based on unique customer names, effectively removing duplicates.

NEW QUESTION # 69
What are the limitations of using a full outer join in a star join node?Note: There are 2 correct answers to this question.

A. Only one column can be included in the join condition.
B. It must appear in the last DIMENSION in the star join node.
C. It CANNOT be mixed in the same star join node with other join types.
D. It is restricted to one DIMENSION in a star join node.

Answer: B,D

NEW QUESTION # 70
In a calculated column, which object do you use to process a dynamic value in an expression?

A. Procedure
B. Variable
C. Input Parameter
D. Table function

Answer: C

Explanation:
AnInput Parameteris used in calculated columns to process dynamic values within expressions. Input parameters can be defined to accept runtime values or calculations, enabling dynamic data manipulation within a calculation view. Variables, in contrast, are primarily used for filtering.

NEW QUESTION # 71
How can you define a variable that presents its value help hierarchically? Note: There are 2 correct answers to this question.

A. Create a parent-child hierarchy and assign it to the variable.
* Ensure the variable's reference column is the child attribute of the hierarchy.
B. Create a level hierarchy and assign it to the variable.
* Ensure the variable's reference column is the top level of the hierarchy.
C. Create a parent-child hierarchy and assign it to the variable.
* Ensure the variable's reference column is the parent attribute of the hierarchy.
D. Create a level hierarchy and assign it to the variable.
* Ensure the variable's reference column is the leaf level of the hierarchy.

Answer: A,D

NEW QUESTION # 72
Why would you implement SQL in calculation views? Note: There are 2 correct answers to this question.

A. To increase the possibilities for consumption
B. To fine-tune performance
C. To implement custom functions
D. To define dynamic analytic privileges

Answer: B,D

Explanation:
* To fine-tune performance (B):Implementing SQL in calculation views can help optimize performance by leveraging advanced SQL features and minimizing unnecessary data movement.
* To define dynamic analytic privileges (D):SQL enables the implementation of conditions for dynamic analytic privileges, ensuring fine-grained and context-sensitive data access.
Options A and C are less relevant as SQL is not primarily for expanding consumption possibilities or implementing functions, which are handled by other mechanisms in SAP HANA.

NEW QUESTION # 73
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